Hydraulic Motor Size Formula:
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The hydraulic motor size calculation determines the displacement volume of a hydraulic motor based on torque requirements and system pressure. This is essential for selecting the appropriate motor for hydraulic systems.
The calculator uses the hydraulic motor size formula:
Where:
Explanation: The formula calculates the displacement needed to produce the required torque at the given system pressure.
Details: Proper motor sizing ensures efficient system operation, prevents overheating, maximizes performance, and extends equipment life. Undersized motors may not deliver required torque, while oversized motors increase cost and reduce efficiency.
Tips: Enter torque in inch-pounds (in-lbs) and pressure in pounds per square inch (psi). Both values must be positive numbers greater than zero for accurate calculation.
Q1: What units should I use for this calculation?
A: This calculator uses imperial units: torque in inch-pounds (in-lbs) and pressure in pounds per square inch (psi).
Q2: What does the result represent?
A: The result represents the displacement volume of the hydraulic motor in cubic inches per revolution (in³/rev).
Q3: Can I use this for hydraulic pumps as well?
A: While the formula is similar, pump sizing typically considers flow requirements rather than torque output. Different calculations are used for pump selection.
Q4: What is the significance of the constant 231?
A: The constant 231 converts between cubic inches and gallons (1 gallon = 231 cubic inches), which is important in hydraulic calculations involving flow rates.
Q5: How does system efficiency affect motor sizing?
A: This calculation provides theoretical displacement. Actual motor selection should account for mechanical efficiency (typically 85-95% for hydraulic motors).